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Minimum JEE Main Marks Required to Qualify for JEE Advanced 2024

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Minimum JEE Main 2024 Marks Required to Qualify For JEE Advanced

Minimum JEE Main 2024 marks required to qualify for JEE Advanced: Lakhs of students appear for the JEE mains exam to further their careers in science, engineering, and architecture. This exam is conducted to analyze the knowledge of the students in the field of science. It is a gateway for students who wish to take (take with a grain of salt idiom synonym) their bachelor’s degree from the renowned engineering institutes of the country. And therefore a good score in the JEE Mains exam is mandatory.

But it must be noted that in order to get admission to the top IITs one must clear the JEE Mains with a good score to be eligible for the JEE Advanced. And after getting a fairly good score in the JEE Advanced the candidates become eligible for a seat in the IIT institutes of the country.

All of this gives rise to the question that every candidate wishing to get a seat in the top engineering institute asks, which is what is the minimum JEE Main score requirement to be eligible for the JEE Advanced?

So, before appearing for the paper the candidates are advised to know everything about it including the minimum score required to be eligible for the JEE Advanced so that the preparation can be done accordingly.

Who announces the Minimum marks in JEE Main?

The National Testing Agency (NTA) will release the minimum qualifying marks for JEE Main 2024 to be eligible for JEE Advanced. The announcement will be made along with the JEE Main 2024 result of session 2, which is expected to be published by the second week of April. To qualify for JEE Advanced, candidates must score above the minimum marks or JEE Main 2024 cutoff, which can be verified by referring to the previous year’s JEE Main cutoff.

JEE Main serves as a screening test for JEE Advanced, which is the gateway to undergraduate engineering courses offered by the IITs. As of last year, the top 2.5 lakh candidates who qualify for JEE Main are eligible to take the JEE Advanced 2024 exam. It is critical for all applicants to achieve a specific score or exceed the JEE Advanced cutoff.

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Expected cutoff for JEE Main 2024

Here, candidates can refer to the previous year’s cutoffs to estimate the expected cutoff for JEE Main 2024. However, the National Testing Agency (NTA) will announce the official cutoff along with the JEE Main 2024 session 1 results in January.

Category JEE Main 2024  ExpectedCutoff
Common Rank List 90-91
Gen-EWS 75-76
OBC-NCL 73-74
SC 51-52
ST 37-38
PwD 0.0013527

JEE Main 2024 Cutoff for JEE Advanced

The minimum marks required for JEE Advanced, as per last year’s cutoff, can be found below for candidates to check. Success in any entrance exam is determined by an effective study plan and the amount of hard work put in by the candidate. With little time (race against time phrase meaning) left, let’s take a quick look at the minimum score required for students to qualify for JEE Advanced 2024. The JEE Main cutoff score required for eligibility to take the JEE Advanced is provided below.

Category JEE Main Cutoff 2023 (Percentile) by NTA
Common Rank List (CRL) 88.4121383
GEN-EWS 63.1114141
Other Backward Classes (OBC-NCL) 67.0090297
Scheduled Caste (SC) 43.0820954
Scheduled Tribe (ST) 26.7771328
PwD 0.0031029

The top 2.5 lakh candidates who qualify for the JEE Advanced would comprise students from unreserved as well as reserved categories. The exam conducting authority will publish the raw score obtained by a candidate in JEE Main as well as the corresponding percentile score. The cut-off for JEE Advanced would be based on the percentile score. Candidates can check the expected cut-off percentile and score required to qualify for the JEE Advanced in the table above.

It is expected that the entrance test will be conducted online at 525 Centres for BTech/BE, 480 centres for BArch and in around 225 cities for BPlanning across the country. The exam acts as a gateway for admission to the Indian Institutes of Technology (IITs) – India’s premier engineering students.

NTA releases the JEE Main 2024 admit card on the official website (idioms website) for eligible candidates only. To download their JEE mains exam admit card, candidates must enter JEE Main login details like their application number and date of birth on the official website. The exam conducting authority is expected to release the official JEE Main 2024 answer key within 3 days post-conclusion of the exam.

Students and parents should note that the expected cutoff provided above is based on the cutoff for 2023. The exact cutoff for 2024 may vary. However, depending on the number of students who appear and the general trends observed over the years, the expected cutoff score remains the same with a variance range of about 5 marks either way.

The percentile of a candidate is the basis for calculating the JEE Main score. As candidates appear for the exam on different shifts on different days, the percentile scores of the students are normalized and calculated as per the formula available on the official website: Joint Entrance Examination (Main). The exam conducting authorities will release the cut-off for JEE Main only after the conclusion of the JEE Man 2024 April exam along with the JEE Main 2024 ranks and final results.

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JEE Main Cut-off Trends

Category/Year 2021 2020
General 87.8992241 90.3765335
OBC-NCL 68.0234447 72.8887969
SC 46.8825338 50.1760245
ST 34.6728999 39.0696101
Gen-EWS 66.2214845 70.2435518
PwD 0.0096375 0.0618524

JEE Main 2024 Dates

Below are the announced exam dates for both the January and April sessions of JEE Main 2024 by the NTA.

Events January Session Dates April Session Dates
Release of Application form Dec-2023 Feb-2024
Last date to fill the form Jan-2024 Mar-2024
Intimation of exam city to candidates Jan-2024 April 1st week
Release of admit card Jan-2024 April 1st week
JEE Main exam date 2024 January 24 To February 1, 2024 April 1, 2024, To April 15, 2024
Display of Answer key Feb-2024 To be notified
Declaration of Result Feb-2024 (tentative) To be notified

Eligibility criteria for JEE Advanced 2024

Every year, the NTA publishes the eligibility criteria for JEE Advanced on its official website, which outlines the requirements and guidelines for applicants. The eligibility criteria for JEE Advanced 2024 are as follows:

  • Candidates who rank within the top 250,000 positions in the JEE Main 2024 exam are eligible to apply for JEE Advanced 2024.
  • Candidates must have attained a minimum of 75% marks in their Class 12 board exams. For candidates belonging to reserved categories, the minimum score required is 65%.
  • Candidates are only allowed to take the JEE Advanced exam twice in consecutive years, regardless of whether they have passed or failed the exam.
  • Applicants who are Indian citizens, foreign nationals, PIOs, or OCIs are eligible to take the JEE Advanced 2024 exam. However, foreign candidates must meet certain criteria set forth by the NTA.

Based on last year’s records, the percentage of reservations for various categories is as follows:

Category Percentage
GEN-EWS 10%
OPEN 40.50%
Scheduled Tribe (ST) 7.50%
Scheduled Caste (SC) 15%
PwD 5% Horizontal Reservation
OBC & NCL 27%

The distribution of the top 250,000* JEE Main candidates for JEE Advanced 2024, categorized by their respective categories, is as follows:

Order Category Number of “Top” candidates
1 OPEN 96187 101250
2 OPEN-PwD 5063
3 GEN-EWS 23750 25000
4 GEN-EWS-PwD 1250
5 OBC-NCL 64125 67500
6 OBC-NCL-PwD 3375
7 SC 35625 37500
8 SC-PwD 1875
9 ST 17812 18750
10 ST-PwD 938

Age limit for JEE Advanced 2024

To be eligible, candidates must have been born on or after October 1, 1997. However, SC, ST, and PwD candidates are given a relaxation of five years, meaning they must have been born on or after October 1, 1992.

JEE Advanced 2024: number of attempts

Candidates can appear for the JEE advanced exam two times in two consecutive years.

JEE Advanced 2024 eligibility for class 12th boards or other equivalent exams

To be eligible for the JEE Advanced 2024 exam, candidates must have cleared their class 12th board exams or equivalent exams beforehand. Candidates who have appeared for their class 12th exams or equivalent exams on or before 2020 are not eligible to take the JEE Advanced exam.

The NTA uses five subjects, namely mathematics, physics, chemistry, optional language, and elective subjects, to calculate the cut-off marks for the class 12th board exams. If the total marks scored in any of the aforementioned subjects are not out of 100, then the marks will be scaled up or down to 100 while calculating the aggregate percentage.

If a candidate appears for the class 12th board exams twice, their best performance out of the two results will be considered for the JEE Advanced 2024 exam. In the event that the examination board for class 12th declares the results late, candidates will still be eligible to take the JEE Advanced 2024 exam provided they meet all other eligibility criteria.

However, if a candidate’s class 12th board result is withheld by the concerned examination body, they will not be allowed to take the JEE Advanced 2024 exam.

The candidates are advised to visit (idioms dictionary) the official website of NTA for more details about the eligibility criteria.

Eligibility for foreign students for JEE Advanced 2024

Candidates who are foreign nationals must meet a separate set of eligibility criteria for JEE Advanced 2024. Foreign nationals are individuals who are neither citizens of India nor have parents of Indian origin. Additionally, candidates who do not belong to the OCI/PIO category are also considered foreign nationals.

The NTA has established certain guidelines for foreign nationals who wish to appear for the JEE Advanced exam. Foreign nationals are not eligible for any reservations under any category as directed by the GOI. They should have completed their 10+2 level education at the time of applying for the JEE Advanced 2024 exam.

Foreign nationals who have completed their class 12th boards in India with the required percentage are considered under the OPEN category for the JEE Advanced exam. They must provide identity proof for both their parents as well.

In the JEE Advanced course, foreign candidates are allocated a total of 10% of the total seats.

JEE Advanced 2024 cut-off

After the conduct of the JEE Advanced exam, the JEE Advanced Cut Off will be announced. The cutoff score refers to the minimum marks that candidates need to obtain in order to secure admission to IITs. The JEE Advanced exam authorities will publish two types of cutoffs – admission cutoffs and qualifying cutoffs.

Several factors influence the JEE Advanced cutoff score, including the previous year’s cutoff trends, the total number of applicants, the difficulty level of the exam, the candidate’s performance in the exam, and the number of seats available for admission.

FAQs: Minimum Marks in JEE Mains to Qualify for JEE Advanced 2024

Q1. Who is eligible for JEE Advanced?

Ans. Candidates who place among the top 2,50,000 in the JEE Main examination are eligible to take the JEE Advanced examination. More information is provided above.

Q2. Can we take the JEE Advanced again?

Ans. Yes, candidates can apply for the JEE Advanced exam twice in a row beginning with the year they complete their 12th grade.

Q3. Is it necessary to take JEE Main before taking JEE Advanced?

Ans. Yes, candidates who want to take the JEE Advanced must be among the top 2,50,000 successful JEE Main candidates.

Q4. What subjects are taken into account for JEE Advanced 2024 eligibility?

Ans. Candidates who want to apply for the JEE Advanced 2024 must have completed Class XII (or equivalent) with the subjects Physics, Chemistry, and Mathematics.

Q5. Do 12th-grade marks count in IIT?

Ans. No, it does not. JEE Advanced gives no weightage to class 12 grades. It will all be determined by their performance on the entrance exam.

Q6. How many points do you need to get into JEE Advanced?

Ans. The expected JEE Main cutoff for general categories in 2024 was around 70-75 points. To be eligible for a seat based on JEE Advanced 2024, students must achieve the specified marks.

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